Respuesta :
The distance from -9 to 7 = 16 units.
Distance from -4 to 8 = 12 units.
Divide the two values and add them to the x and y values of the first set and the result will be our midpoint.
16/2 = 8. 8 + -9 = -1
12/2 = 6. 6 + -4 = 2
So our midpoint will be (-1,2)
Distance from -4 to 8 = 12 units.
Divide the two values and add them to the x and y values of the first set and the result will be our midpoint.
16/2 = 8. 8 + -9 = -1
12/2 = 6. 6 + -4 = 2
So our midpoint will be (-1,2)
Answer:
( -1 , 2 ) is the mid point of the line segment JK.
Step-by-step explanation:
Given coordinates of the points are J( -9 , -4 ) and K( 7 , 8 )
We have to find Mid point of Line segment JK.
Coordinates of mid points are given by = [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
here [tex](x_1,y_1)=(-9,-4)\:\:and\:\:(x_1,y_2)=(7,8)[/tex]
So, Coordinates of the Mid Point of JK = [tex](\frac{-9+7}{2},\frac{-4+8}{2})[/tex]
= [tex](\frac{-2}{2},\frac{4}{2})[/tex]
= [tex](-1,2)[/tex]
Therefore, ( -1 , 2 ) is the mid point of the line segment JK.