What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)? y + 3 = −4(x + 4) y + 3 = –(x + 4) y + 3 = (x + 4) y + 3 = 4(x + 4)

The slope of the perpendicular lines are inverse and opposite to each other.
The equation of the perpendicular line is,
[tex]y+3=\dfrac{1}{4}(x+4)[/tex]
Thus the option 4 is the correct.
The equation of the line is the way of representation of a line in the equation form.
The equitation of the lines represents the line by the set of points on which the line lies or passes through in the coordinate system.
Given information-
The point from which the perpendicular lines passes are (-4,-3).
The equation of this line can be given as,
[tex](y-y_1)=m(x-x_1)[/tex]
Here, [tex]m[/tex] is the slope of the line. The slope of the line can be given as,
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
The point of the given line though which the line passes are (-1,1), and (0,-3).
Put the values,
[tex]m=\dfrac{-3-(-1)}{0-1}\\m=-4[/tex]
Thus the slope of the given line is -4. Now the slope of the perpendicular lines are inverse and opposite to each other.
Thus the slope of the line which is perpendicular to the is 1/4.
The point from which the perpendicular lines passes are (-4,-3) and the slope if 1/4. Thus its equation is,
[tex](y-(-3))=\dfrac{1}{4}(x-(-4))\\y+3=\dfrac{1}{4}(x+4)[/tex]
Hence the equation of the perpendicular line is,
[tex]y+3=\dfrac{1}{4}(x+4)[/tex]
Thus the option 4 is the correct.
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