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The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6Li + N2 mc007-1.jpg 2Li3N If 12 mol of lithium were reacted with excess nitrogen gas, how many moles of lithium nitride would be produced?
4.0 mol
6.0 mol
12 mol
36 mol

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Dejanras

Answer is: 4.0 mol of lithium nitride would be produced.

Balanced chemical reaction: 6Li + N₂ → 2Li₃N.

n(Li) = 12 mol; amount of substance.

From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).

n(Li₃N) = n(Li) ÷ 3.

n(Li₃N) = 12 mol ÷ 3.

n(Li₃N) = 4 mol; amount of lithium nitride.

amovoce

Answer:

4.0 mol

Explanation:

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