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∆ABC rotates around point D to create ∆A′B′C′.

Based on the position of B'C', shown in the figure, the coordinates of A′ are (4,1)(4,7)(6,1)(6,7).

If ∆A′B′C′ rotates 90° counterclockwise around point E(7, 5) to form triangle ∆A″B″C″, the coordinates of A″ are (3,6)(7,2)(7,6)(11,2).

ABC rotates around point D to create ABC Based on the position of BC shown in the figure the coordinates of A are 41476167 If ABC rotates 90 counterclockwise ar class=

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nobillionaireNobley
Given that ∆ABC rotates around point D to create ∆A′B′C′.
 
Line BC is a horizontal line such that the length of BC is 2 units. Also line AB is a vertical line such that the length of AB is 3 units.

Based on the position of B'C', shown in the figure, the coordinates of A′ are will be vertical to the cordinate of B' going downwards with a length of 3 units. This means that the x-value of the coordinate of A' is the same as that of B' but the y-value of the coordinate of A' is 3 units less than that of B'.

The coordinate of B' is (4, 4).
Therefore, the coordinate of A' is (4, 4 - 3) = (4, 1).
dhevannnyahhh

Answer:

Option A: (4, 1)

Option D: (11, 2)

Explanation:

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