Answer:
Total resistance, R' = 3 ohms
Explanation:
It is given that, a circuit contains two devices that are connected in parallel. There values are given as :
Resistor 1, [tex]R_1=12\ \Omega[/tex]
Resistor 2, [tex]R_2=4\ \Omega[/tex]
The total resistance in parallel combination is given by :
[tex]\dfrac{1}{R'}=\dfrac{1}{R_1}+\dfrac{1}{R_2}[/tex]
[tex]\dfrac{1}{R'}=\dfrac{1}{12}+\dfrac{1}{4}[/tex]
R' = 3 ohms
So, the total resistance of the two devices is 3 ohms. Hence, this is the required solution.
