For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.
Therefore, the following lengths are the same:
[tex] GH = HK
[/tex]
So, by equalizing both sides we have:
[tex] 5m + 1 = 3m + 7
[/tex]
From here, we clear the value of m.
We have then:
[tex] 5m - 3m = 7 - 1
2m = 6
[/tex]
[tex] m = \frac{6}{2}
m = 3
[/tex]
Answer:
The value of m is given by:
[tex] m = 3 [/tex]
