3 seconds
In this case;
Final velocity = 0 m/s (because the car is going to rest by stopping)
Initial velocity = 24 m/s
Acceleration = -8.0 m/s²
Thus; - 8.0 m/s² = (0-24 m/s)/ t
time = (-24 m/s)/-8.0 m/s²
= 3 seconds
The car will take 3 seconds to stop at red light.
Given data:
The initial speed of car is, u = 24 m/s.
The magnitude of acceleration of car is, [tex]a=-8.0 \;\rm m/s^{2}[/tex].
The final speed of car is, v = 0 m/s. (Since car stops at red light)
Apply the first kinematic equation of motion to obtain the time taken by car to stop at red light as,
[tex]v=u+at[/tex]
Substituting the values as,
[tex]0=24+(-8)t\\8t=24\\t=3\;\rm s[/tex]
Thus, we can conclude that car will take 3 seconds to stop at red light.
Learn more about the kinematic equations of motion here:
https://brainly.com/question/13202575
