Respuesta :
the answer
the general equation of the reaction is
NH4NO3 -------------- N2O + 2H2O
The molar mass of NH4NO3 is 80.03
The mass of NH4NO3 is 160.1 g
so we can deduce that
nNH4NO3 = number of mole of NH4NO3 = 160.1 g / 80.03 =2 moles
by using proportion property
NH4NO3 -------------- N2O + 2H2O
1mole 1mole 2 moles
nNH4NO3 nH2O
the number of mole nH2O can be found by
1/ nNH4NO3 = 2 / nH2O
nH2O = 2 x nNH4NO3 = 2 x 2 = 4 moles
to find the mass, we use
mH2O = 4 moles x 18.01 g /mol = 36 g
the general equation of the reaction is
NH4NO3 -------------- N2O + 2H2O
The molar mass of NH4NO3 is 80.03
The mass of NH4NO3 is 160.1 g
so we can deduce that
nNH4NO3 = number of mole of NH4NO3 = 160.1 g / 80.03 =2 moles
by using proportion property
NH4NO3 -------------- N2O + 2H2O
1mole 1mole 2 moles
nNH4NO3 nH2O
the number of mole nH2O can be found by
1/ nNH4NO3 = 2 / nH2O
nH2O = 2 x nNH4NO3 = 2 x 2 = 4 moles
to find the mass, we use
mH2O = 4 moles x 18.01 g /mol = 36 g