Answer: The house is 12 feet 10 inches far from the other side of the lot .
Step-by-step explanation:
Since we have given that
Size of a home = 61 foot 6 inches wide lot
We first convert it into inches,
so, we get,
[tex]61\times 12+6=738\ inches=a[/tex]
Size of the house from the side of the lot = 7 feet 2 inches
So, it becomes
[tex]7\times 12+2=84+2=86\ inches=b[/tex]
So, We get,
[tex]a-b=738-86=652=c\ inches[/tex]
Now, we have,
Width of the house = 41 foot 6 inches
So, it becomes
[tex]41\times 12+6=498\ inches=d[/tex]
So, house is far from the other side of the lot is given as
[tex]c-d=652-498=154\ inches[/tex]
Hence, The house is 154 inches far from the other side of the lot .
i.e.
[tex]\frac{154}{12}=12\ feet\ 10\ inches[/tex]
