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How many grams of a stock solution that is 85.5 percent H2SO4 by mass would be needed to make 150 grams of a 45.0 percent by mass solution? Show all of the work needed to solve this problem.

Respuesta :

mergl
(150 grams)(45/100)=(x)(85.5/100)
67.5=.855(x)
x=78.947368 grams of stock solution

Answer : The mass of stock solution needed, 78.94 grams

Solution :

Formula used :

[tex]C_1m_1=C_2m_2[/tex]

where,

[tex]C_1[/tex] = amount of stock solution needed = ?

[tex]C_2[/tex] = amount of stock solution given = 150 g

[tex]m_1[/tex] = mass percent of [tex]H_2SO_4[/tex] = 85.5 %

[tex]m_2[/tex] = mass percent of solution = 45 %

Now put all the given values in the above relation, we get

[tex]C_1\times \frac{85.5}{100}=(150g)\times \frac{45}{100}[/tex]

[tex]C_1=78.94g[/tex]

Therefore, the mass of stock solution needed, 78.94 grams

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