Respuesta :
We do completing the square as follows:
Write the equation in such a way that the constants are on one side.
x^2 + 2x = 13
We add a number to both sides that will complete the square on the side which contains the variable x.
x^2 + 2x + 1 = 13 +1
We factor the side which contains the variable x.
(x+1)^2 = 14
Therefore, we should add 1 in order to complete the square from the given equation.
Write the equation in such a way that the constants are on one side.
x^2 + 2x = 13
We add a number to both sides that will complete the square on the side which contains the variable x.
x^2 + 2x + 1 = 13 +1
We factor the side which contains the variable x.
(x+1)^2 = 14
Therefore, we should add 1 in order to complete the square from the given equation.
Answer:
The answer is 1
Step-by-step explanation:
In order to complete the square, you have to know the rule for expanding a square of a binomial.
The rule says:
Let [tex](a+b)^2[/tex] a square of a binomial in general
The square of any binomial produces the following three terms:
1. The square of the first term of the binomial: [tex]a^2[/tex]
2. Twice the product of the two terms: [tex]2*a*b[/tex]
3. The square of the second term: [tex]b^2[/tex]
So, the expand of a square of a binomial is:
[tex](a+b)^2=a^2+2*a*b+b^2[/tex]
Therefore, we should think which of the three terms mentioned before it is absent.
1. First term is [tex]x^2[/tex]
2. Second term is [tex]2*x[/tex]
3. Third term must be [tex]1[/tex] because it is the unique number which multiplying by [tex]x[/tex] results in [tex]2*x[/tex]
Finally, adding 1 in both side of the equation:
[tex]x^2+2*x+1=13+1\\(x+1)^2=14[/tex]