Respuesta :

mreijepatmat
In an isosceles triangle the sides XY &  YZ are equal, as well as the angles oppose to those sides:

∠ X = ∠ Z  and ∠ Y = a° (given)

We know that ∠X + ∠ Z + ∠ Y =180°, Since ∠ X = ∠ Z, then:

2(X) + a° =180°, X = a°/2 +90°

Answer:

2(X) + a° =180°, X = a°/2 +90°

Step-by-step explanation:

In an isosceles triangle the sides XY &  YZ are equal, as well as the angles oppose to those sides:

∠ X = ∠ Z  and ∠ Y = a° (given)

We know that ∠X + ∠ Z + ∠ Y =180°, Since ∠ X = ∠ Z, then:

2(X) + a° =180°, X = a°/2 +90°