Option D: 246 K
According to ideal gas law:
[tex]PV=nRT[/tex] ...... (1)
Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature of the gas. The value of R is [tex]0.082 atm L K^{-1}mol^{-1}[/tex].
Number of moles of gas are 0.750 mol, volume of cylinder is 6850 mL and pressure of gas is 2.21 atm.
First converting volume from mL to L
[tex]1 mL=10^{-3}L[/tex]
Thus,
6850 mL=6.850 L
Putting the values in equation (1),
[tex](2.21 atm)(6.850 L)=(0.750 mol)(0.082 atm L K^{-1}mol^{-1}T[/tex]
Rearranging
[tex]T=\frac{(2.21 atm)(6.850 L)}{(0.750 mol)(0.082 atm L K^{-1}mol^{-1})}=246 K[/tex],
Therefore, temperature of the gas is 246 K.
