Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After running for 54 minutes, she completes 6 kilometers. Her trainer writes an equation letting t, the time in minutes, represent the independent variable and k, the number of kilometers, represent the dependent variable.

Which equation can be used to represent k, the number of kilometers Julissa runs in t minutes?

k – 2 = (t – 18)
k – 18 = (t – 2)
k – 2 = 9(t – 18)
k – 18 = 9(t – 2)

Respuesta :

Answer:

The required equation [tex]k-2=\dfrac{1}{9}(t-18)[/tex]

C should be correct.

Step-by-step explanation:

Given: Julissa is running a 10-kilometer race at a constant pace.

After running for 18 minutes, she completes 2 kilometers.

First point: (18,2)

After running for 54 minutes, she completes 6 kilometers.

Second Point: (54,6)

We need to write an equation letting t, the time in minutes, represent the independent variable and k, the number of kilometers, represent the dependent variable

Using two point formula to find the equation of line

Formula:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Required Equation:

[tex]k-2=\dfrac{6-2}{54-18}(t-18)[/tex]

[tex]k-2=\dfrac{4}{36}(t-18)[/tex]

[tex]k-2=\dfrac{1}{9}(t-18)[/tex]

Hence, The required equation [tex]k-2=\dfrac{1}{9}(t-18)[/tex]

Answer:

The required equation [tex]k-18=9(t-2)[/tex] represent [tex]k,[/tex] the number of kilometers Julissa runs in [tex]t[/tex] minutes.

Step-by-step explanation:

Given: Julissa is running a [tex]10[/tex]-kilometer race at a constant pace. After running for [tex]18[/tex] minutes, she completes [tex]2[/tex] kilometers. After running for [tex]54[/tex] minutes, she completes [tex]6[/tex] kilometers.

According to question:

After running for [tex]18[/tex] minutes, she completes [tex]2[/tex] kilometers.

After running for [tex]54[/tex] minutes, she completes [tex]6[/tex] kilometers.

Considering these values in the form of points [tex](2, 18)\; \&\; (6, 54)[/tex].

We have to write an equation letting [tex]t,[/tex] the time in minutes, represent the independent variable and [tex]k,[/tex] the number of kilometers, represent the dependent variable.

Using two point-slope form of straight line:

[tex]y-y_{1} =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } (x-x_{1} )[/tex]

Putting the points to get the equation:

[tex]k-18=\frac{54-18}{6-2}(t-2)\\k-18=\frac{36}{4} (t-2)\\k-18=9(t-2)[/tex]

Therefore, the required equation is [tex]k-18=9(t-2)[/tex].

Hence, the correct option is [tex]d[/tex].

Learn more about  two point-slope form of straight line here:

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