Respuesta :

Sn    +    2HF ----> SnF₂ + H₂
119g     2×20g

1 mole Sn (119g) is required to react with 2 moles (40g) of HF.

:)

Answer:

1 mole of Sn

Explanation:

Tin (Sn) reacts with hydrogen fluoride (HF) to form stannous fluoride (SnF2), a compound that is used in toothpaste to strengthen tooth enamel. Another product of this reaction is the H2 that is released as gas.

                                          Sn + HF  ⇒ SnF₂ + H₂

Once we have the equation, we balance it on both sides.

                                      Sn + 2  HF  ⇒ SnF₂ +  H₂  

To make the following calculation we have to find out how much a mole of Sn weighs.

Sn= 118.69 g/mol

HF = 20.01 g/mol

      Sn        +     2  HF               ⇒    SnF₂    +     H₂

  118.69 g        2 x 20.01 g

  118.69 g  <----  40.02 g

Every 2 moles of HF (40.02g) reacts 1 mole of Sn.