The pH of 0.010 M KOH solution in which KOH is a strong base KOH → K⁺ + OH⁻ is 12.
pH is the measurement of the acidity and basicity of any solution.
pH = 14 - pOH
pOH = -log [OH⁻]
pH = 14 + log [OH⁻]
pH = 14 + log0.010 = 14 - 2 = 12
pH = 12
Thus, the pH = 12.
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