Respuesta :

angelicdragon12
distance formula: [tex] \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y{1})^{2}} [/tex]

[tex]\sqrt{(-2-6)^{2}+(8-(-2))} \\ \sqrt{(-8)^{2}+(10)^{2}} \\ \sqrt{64+100} \\ \sqrt{164} = 2\sqrt{41} = 12.8062 = 12.8[/tex]
firestarangel26
Distance formula: 
[tex] \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} [/tex]

We are given 2 coordinates: 
(-2,8) and (6,-2) 
x1,y1        x2,y2

Plug the numbers into the formula: 

[tex] \sqrt{(6-(-2))^2+(-2-8)^2} [/tex]

Simplify: 
[tex] \sqrt{(8)^2+(-10)^2} [/tex]

8^2=64
-10^2=100
[tex] \sqrt{100+64} [/tex]
[tex] \sqrt{164}=12.806248474865697[/tex]

The question asks to round to the nearest tenth so final answer: 
12.8

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