Respuesta :
[H⁺] = 1,7×10⁻⁹ mol/dm³
pH = -log[H⁺]
pH = -log[1,7×10⁻⁹]
pH = 8,77
pH + pOH = 14
pOH = 14-8,77
pOH = 5,23
:)
pH = -log[H⁺]
pH = -log[1,7×10⁻⁹]
pH = 8,77
pH + pOH = 14
pOH = 14-8,77
pOH = 5,23
:)
Answer : The pOH of the solution is, 5.24
Solution : Given,
Concentration of [tex]H^[/tex] = [tex]1.7\times 10^{-9}M[/tex]
As we know that the pH is the negative logarithm of the hydrogen ion concentration.
First we have to calculate the pH of the solution.
[tex]pH=-\log [H^+][/tex]
[tex]pH=-\log (1.7\times 10^{-9})=8.76[/tex]
Now we have to calculate the pOH.
[tex]pH+pOH=14[/tex]
[tex]8.76+pOH=14[/tex]
[tex]pOH=5.24[/tex]
Therefore, the pOH of the solution is, 5.24