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10 Points.) A stone weighing 0.7 kilograms rolls down the inclined plane from position B to position A. Position A is located at sea level. The Inclined Plane is 0.25 Meters high.  The difference in the gravitational potential energy of the ball between positions A and B is about___ joules. (Use PE = m × g × h, where g = 9.8 N/kg.)

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williamclement0
The potential energy of the moss is 147 Joules

Answer : 1.715 J

Explanation :

It is given that :

Mass of stone, m = 0.7 kg

The ball rolls down the inclined position from B to A and position A is located at sea level.

Height of inclined plane, h = 0.25 m

Gravitational potential energy at point A = 0 ( since, at point A PE = 0 )

Gravitational potential energy at point B = m g h

where,

m is the mass of ball

g is acceleration due to gravity

h is the height

So, at B potential energy will be :

[tex]PE_B=0.7\ kg\times 9.8\ m/s^2\times 0.25\ m[/tex]

[tex]PE_B =1.715\ J[/tex]

So, the difference in the gravitational potential energy of the ball between positions A and B is :

[tex]PE_B-PE_A=1.715\ J[/tex]

Hence, this is the required solution.

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