Ans) 6
The given equation is:
BF3 + Li2SO3 → B2(SO3)3 + LiF
# atoms in Reactants # atoms in Products
B = 1 B = 2
F = 3 F = 1
Li = 2 Li = 1
S = 1 S = 3
O = 3 O = 9
In order to balance the unequal distribution of atoms, multiply BF3 by 2, Li2SO3 by 3 and LiF by 6 to get:
2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF
Coefficient of LiF = 6
