Step-by-step explanation:
We have
log(x² - 15) = log(2x)
Solving the equation
x² - 15 = 2x
x² - 2x - 15 = 0
(x-5)(x+3) = 0
x -5 = 0 or x + 3 = 0
x = 5 or x = -3
The solutions are −3 and 5.
Order of solution is x² − 15 = 2x, x² - 2x - 15 = 0, (x − 5)(x + 3) = 0, x − 5 = 0 or x + 3 = 0 and potential solutions are −3 and 5.
Order is 3,1,5,2 and 4.
The order of steps to solve the equation [tex]\rm log (x^2-15) = log(2x)[/tex] form 1 to 5.
3
1
5
4
2
[tex]\rm x^2 -2x-15 =0[/tex] (1)
Potential solutions are −3 and 5 (2)
[tex]\rm x^2 -15 = 2x[/tex] (3)
x − 5 = 0 or x + 3 = 0 (4)
(x − 5)(x + 3) = 0 (5)
The given equation is formulated below
[tex]\rm log (x^2-15) = log(2x)[/tex]
[tex]\rm Removing\; log\; from \; both \; the\; sides \; we \; get \\x^2 -15 = 2x\\x^2 -2x -15 =0 \\ (x+3)(x-5) =0 \\Solving\; for\; x\; gives \\x = -3, x =5[/tex]
From the above observations of the solution we can say that order of solution for equation [tex]\rm log (x^2-15) = log(2x)[/tex] is
3
1
5
4
2
For more information please refer to the link below
https://brainly.com/question/16467975
