Respuesta :

1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles C₆H₁₂O₆ ----------- X
X = (3
×6)/1
X = 18 moles

:)

Answer is: there are 18 moles of oxygen in 3.0 mol of glucose.

n(C₆H₁₂O₆) = 3.0 mol; amount of glucose.

In one molecule of glucose (C₆H₁₂O₆) there are six oxygen atoms:

nn(C₆H₁₂O₆) : n(O) = 1 : 6.

3.0 mol : n(O) = 1 : 6.

n(O) = 3.0 mol · 6.

n(O) = 18.0 mol; amount of oxygen atoms.