Answer:
The correct option is A.
Step-by-step explanation:
We have to prove ΔBDF and ΔCAE are similar.
Two triangles are called similar if their corresponding interior angles are same or the corresponding sides are in a proportion.
According to the property of similarity, if two corresponding angles of triangles are same then the triangles are similar.
To prove,
[tex]\triangle BDF\sim \triangle CAE[/tex]
The required conditions are
[tex]\angle B\cong \angle C[/tex] .... (1)
[tex]\angle D\cong \angle A[/tex] .... (2)
[tex]\angle F\cong \angle E[/tex] .... (3)
If any two conditions from the above mentioned conditions are given then we can say that the ΔBDF and ΔCAE are similar.
Only option A satisfies the condition 1 and 3 because,
[tex]\angle GBH\cong \angle ICH[/tex]
[tex]\angle BFD\cong \angle CEF[/tex]
If these angles are congruent, then by AA rule of similarity ΔBDF and ΔCAE are similar.
Option A is correct.