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A pharmaceutical company collects data on the side effects participants report for a drug it is testing. The company finds that the probability of experiencing a headache is 5 percent and the probability of experiencing both a headache and heartburn is 2 percent. If the probability of experiencing a headache or heartburn is 8 percent, what is the probability of experiencing heartburn?

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the answer is 5 percent , i just did it on edgen

Using Venn probabilities, it is found that there is a 0.05 = 5% probability of experiencing heartburn.

In this question:

  • Event A: Headache.
  • Event B: Heartburn.

The probability of experiencing a headache is 5 percent and the probability of experiencing both a headache and heartburn is 2 percent, hence:

[tex]P(A) = 0.05, P(A \cap B) = 0.02[/tex]

The probability of experiencing a headache or heartburn is 8 percent, hence:

[tex]P(A \cup B) = 0.08[/tex]

We want to find P(B), hence:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

[tex]0.08 = 0.05 + P(B) - 0.02[/tex]

[tex]0.03 + P(B) = 0.08[/tex]

[tex]P(B) = 0.05[/tex]

0.05 = 5% probability of experiencing heartburn.

A similar problem is given at https://brainly.com/question/24707032

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