Answer: The volume of NaOH comes out to be 26.14 mL.
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=2\\M_1=0.132M\\V_1=10mL\\n_2=1\\M_2=0.101M\\V_2=?mL[/tex]
Putting values in above equation, we get:
[tex]2\times 0.132\times 10=1\times 0.101\times V_2\\\\V_1=26.14mL[/tex]
Hence, the volume of NaOH comes out to be 26.14 mL.
