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C6H6 + 02 forms CO2 + H20
Complete with factors to stabilize
C6H6 + 15/2 O2 forms 6 CO2 + 3 H2O
You take away only the info you need
C6H6 15/2 O2
1 mol 15/2 or 7,5 mol

15/2 or 7,5 mol of O2 are required.

;)
Giangiglia

Answer:

7.5 mol of oxygen are required

Explanation:

Hi, as it says, this is a combustion reaction of benzene:

[tex]C_6H_6(l) + O_2(g) \longrightarrow CO_2 (g) + H_2O (g)[/tex]

The first step is to balance the equation:

1 mol of [tex]CO_2[/tex] for each C in the benzene

1 mol of [tex]H_2O[/tex] for each two H in the benzene

1 mol of [tex]O_2[/tex] for each [tex]CO_2[/tex] and 0.5 mol for each [tex]H_2O[/tex]

Balanced:

[tex]C_6H_6(l) + 15/2 O_2(g) \longrightarrow 6 CO_2 (g) + 3 H_2O (g)[/tex]

Now, following the reaction:

For 1 mol of benzene, 15/2 (7.5) mol of oxygen are required.  

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