Respuesta :
2С⁻¹₂Н₂ + 5O⁰₂ → 4C⁺⁴O⁻²₂ + 2Н₂О⁻²
the oxidation process:
С⁻¹ - 5e⁻ = C⁺⁴ carbon is the reducing agent
the reduction process:
O⁰₂ + 4e⁻ = 2O⁻² oxygen is the oxidizer
the oxidation process:
С⁻¹ - 5e⁻ = C⁺⁴ carbon is the reducing agent
the reduction process:
O⁰₂ + 4e⁻ = 2O⁻² oxygen is the oxidizer
The reaction has consisted of both oxidation and reduction, thus the reaction has been a redox reaction.
Oxidation can be defined as the gain of electrons in a chemical reaction. In terms of oxidation state, the increase in the oxidation state has been defined as oxidation.
The Reduction has been the loss of electrons in a chemical reaction. The oxidation state of the element decreases in the reduction.
In the given reaction, the oxidation states of the elements are:
[tex]\rm 2\;C_2H_2\;+\;5O_2\;\rightarrow\;4\;CO_2\;+\;2\;H_2O[/tex]
-1 0 +4 -2 -2 Oxidation states
The carbon has lost electrons and the oxidation state of carbon has been changed from -1 to +4. Thus the reaction has been oxidation.
The oxidation reaction will be:
C - 5 electrons = C
The oxygen has gained electrons and the oxidation state of oxygen has been changed from 0 to -2. Thus the reaction has been reduction.
The reduction reaction will be:
O + 4 electrons = O.
The reaction has consisted of both oxidation and reduction, thus the reaction has been a redox reaction.
For more information about the redox reaction, refer to the link:
https://brainly.com/question/13978139