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The reaction for the combustion of acetylene is shown. Explain why this reaction is a redox reaction by identifying the oxidation numbers that change, what is oxidized, what is reduced, and what happens to the electrons during the reaction.

2C2H2 + 5O2 → 4CO2 + 2H2O


Respuesta :

2С⁻¹₂Н₂ + 5O⁰₂ → 4C⁺⁴O⁻²₂ + 2Н₂О⁻²

the oxidation process:
С⁻¹ - 5e⁻ = C⁺⁴   carbon is the reducing agent

the reduction process:
O⁰₂ + 4e⁻ = 2O⁻²   oxygen is the oxidizer

The reaction has consisted of both oxidation and reduction, thus the reaction has been a redox reaction.

Oxidation can be defined as the gain of electrons in a chemical reaction. In terms of oxidation state, the increase in the oxidation state has been defined as oxidation.

The Reduction has been the loss of electrons in a chemical reaction. The oxidation state of the element decreases in the reduction.

In the given reaction, the oxidation states of the elements are:

[tex]\rm 2\;C_2H_2\;+\;5O_2\;\rightarrow\;4\;CO_2\;+\;2\;H_2O[/tex]

   -1             0           +4  -2            -2     Oxidation states

The carbon has lost electrons and the oxidation state of carbon has been changed from -1 to +4. Thus the reaction has been oxidation.

The oxidation reaction will be:

C - 5 electrons = C

The oxygen has gained electrons and the oxidation state of oxygen has been changed from 0 to -2. Thus the reaction has been reduction.

The reduction reaction will be:

O + 4 electrons = O.

The reaction has consisted of both oxidation and reduction, thus the reaction has been a redox reaction.

For more information about the redox reaction, refer to the link:

https://brainly.com/question/13978139