Respuesta :
Answer:
The equation of the line passing through the points (2, –1) and (5, –10) is y = -3x + 5 .
Step-by-step explanation:
The equation of a slope is given by
[tex](y - y_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x - x_{1})[/tex]
As the line passing through the points (2, –1) and (5, –10) .
Put all the values in the above
[tex](y - (-1)) = \frac{-10-(-1)}{5-2}(x - 2)[/tex]
[tex](y + 1) = \frac{-10+1 }{5-2}(x - 2)[/tex]
[tex](y + 1) = \frac{-9}{3}(x - 2)[/tex]
3y + 3 = -9x -9 × -2
3y + 3 = -9x + 18
3y = -9x + 18 -3
3y = -9x + 15
Simplify the above
3y = 3 (-3x + 5)
y = -3x + 5
Therefore the equation of the line passing through the points (2, –1) and (5, –10) is y = -3x + 5 .
