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A 2 µC charge q1 and a 2 µC charge q2 are 0.3 m from the x-axis. A 4 µC charge q3 is 0.4 m from the y-axis. The distances d13 and d23 are 0.5 m. Find the magnitude and direction of the resulting vector R. Round your answer to the nearest tenth. The magnitude is N. The direction is °.

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Here's the answer ladies and gents
Magnitude : 0.5n
Direction  : 0 degrees.

The force is directly proportional to the product of the two charges. The magnitude of the force between given charges is 4.4 N.

What is Coulomb's law?

The electrostatic force is directly proportional to the product of the two charges and indirectly proportional to the distance between them.

[tex]F = \dfrac {Q_1Q_2 }{r^2}[/tex]

Where,

[tex]F[/tex] - Force

[tex]Q_1 [/tex]- Charge of first particle =  2 C

[tex]Q_2 [/tex]- Charge of second particle= 2 C

[tex]r [/tex]- distance between particles = 0.3 m

Put the values in the formula,

[tex]F= \dfrac {2\times 2}{0.3^2}\\\\F = \dfrac 4{0.9}\\\\F= 4.4[/tex]

Therefore, the magnitude of the force between given charges is 4.4 N.

To know more about Coulomb's law:

https://brainly.com/question/506926

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