The vertices A(–2, –1), B(–3, 2), C(–1, 3), and D(0, 0) form a parallelogram. The vertices A’(–1, –2), B’(2, –3), C’(3, –1), and D’(0, 0) are the image of the parallelogram after a sequence of transformations. Which sequence of transformations could produce the image from the pre-image?

Respuesta :

Solution:

Vertices of Preimage  i.e the shape which is a parallelogram=A(–2, –1), B(–3, 2), C(–1, 3), and D(0, 0)

A transformation is done on the Preimage to get image

Vertices of image  i.e the shape which is a parallelogram=A’(–1, –2), B’(2, –3), C’(3, –1), and D’(0, 0)

Reflection along a line(Mirror) has taken place , the reason being that the points are inverted i.e (a,b) is replaced by (b,a).

Ver imagen Аноним

Answer:

Solution:

Vertices of Pre-image  i.e the shape which is a parallelogram=A(–2, –1), B(–3, 2), C(–1, 3), and D(0, 0)

A transformation is done on the Pre-image to get image

Vertices of image  i.e the shape which is a parallelogram=A’(–1, –2), B’(2, –3), C’(3, –1), and D’(0, 0)

Reflection along a line(Mirror) has taken place , the reason being that the points are inverted i.e (a,b) is replaced by (b,a).