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A gas has an initial volume of 15.4 L at a pressure of 1.5 atm and a temperature of 310 K. The pressure of the gas decreases to 0.9 atm as the temperature decreases to 268 K. What is the final volume of the gas? Round your answer to the nearest tenth.
ANSWER: 22.2 L

Respuesta :

mergl
PV=nRT
(1.5)(15.4)=(n)(0.08201)(310)
(PV)/(RT)=n
n=0.9086224733 atm
(0.9)(V)=(0.9086224733)(0.08201)(268)
(P)/(nRT)=V
V=22.18924731L
V=22.2L

Answer : The final volume of gas is, 22.2 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 1.5 atm

[tex]P_2[/tex] = final pressure of gas = 0.9 atm

[tex]V_1[/tex] = initial volume of gas = 15.4 L

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = 310 K

[tex]T_2[/tex] = final temperature of gas = 268 K

Now put all the given values in the above equation, we get:

[tex]\frac{1.5atm\times 15.4L}{310K}=\frac{0.9atm\times V_2}{268K}[/tex]

[tex]V_2=22.189L\approx 22.2L[/tex]

Therefore, the final volume of gas is, 22.2 L

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