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A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 meters/second in 3 seconds. What’s the acceleration of the motorcycle over this time? Use . 9 m/s2 8 m/s2 6 m/s2 5 m/s2 3 m/s2

Respuesta :

skyluke89

Answer: [tex]3 m/s^2[/tex]

Explanation:

The acceleration of the motorcycle is given by

[tex]a=\frac{v-u}{t}[/tex]

where

v=24 m/s is the final velocity of the motorcycle

u=15 m/s is the initial velocity

t=3 s is the time taken

Substituting these numbers into the equation, we find

[tex]a=\frac{24 m/s-15 m/s}{3 s}=\frac{9 m/s}{3s}=3 m/s^2[/tex]

facundo3141592

Answer: 3 m/s^2

Explanation: The acceleration is defined as the rate of change of the velocity:

We know that at the time t = 0 the velocity was 15 m/s

and at the time t = 3s the velocity was 24 m/s

Then the average acceleration may be calculated as the slope of the linear relationship between these two points; this is if the points are (0, 15) and (3, 24)

The slope is : S = (23 - 15)/(3 - 0)m/s^2 = 3m/s^2

So the average acceleration of the motorcycle in this period of time is 3 meters per second squared.

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