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An airplane is flying at an altitude of 10,000 feet. The pilot notices that the beginning of the runway where he plans to land is at an angle of depression of 13 degrees with the horizontal.How far horizontally must he fly to be directly over the runway?

Respuesta :

Tylerftroop
13,000 feet I believe
Blacklash

Answer:

43314.76 ft horizontally he must fly to be directly over the runway

Step-by-step explanation:

Refer the figure given

We have altitude of aeroplane = BC = 10000 ft

The pilot notices that the beginning of the runway where he plans to land is at an angle of depression of 13 degrees with the horizontal

             ∠CAB = 13°

We need to find how far horizontally must he fly to be directly over the runway = AB

We have

         [tex]tan13=\frac{BC}{AB}=\frac{10000}{AB}\\\\AB=43314.76 ft[/tex]

43314.76 ft horizontally he must fly to be directly over the runway

Ver imagen Blacklash

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