Respuesta :
(4x-1)^2=11
First we're going to get rid of the square so:
4x - 1 = [tex] \sqrt{11} [/tex]
Next we move -1 to the other side
4x - 1 + 1 = [tex] \sqrt{11} [/tex]+ 1
Which becomes 4x = [tex] \sqrt{11} [/tex] + 1
Last, we divide by 4
x = 1/4 + [tex] \sqrt{11} [/tex] ; 1/4 - [tex] \sqrt{11} [/tex]
First we're going to get rid of the square so:
4x - 1 = [tex] \sqrt{11} [/tex]
Next we move -1 to the other side
4x - 1 + 1 = [tex] \sqrt{11} [/tex]+ 1
Which becomes 4x = [tex] \sqrt{11} [/tex] + 1
Last, we divide by 4
x = 1/4 + [tex] \sqrt{11} [/tex] ; 1/4 - [tex] \sqrt{11} [/tex]