[tex]16. \ \ \frac{3}{x-3}- \frac{5}{x-2}=\frac{3(x-2)-5(x-3)}{(x-3)(x-2)}=\frac{3x-6-5x+15}{(x-3)(x-2)}=\frac{-2x+9}{(x-3)(x-2)}[/tex]
[tex]17. \ \ \frac{7}{x-3}+ \frac{3}{x-5}=\frac{7(x-5)+3(x-3)}{(x-3)(x-5)}=\frac{7x-35+3x-9}{(x-3)(x-5)}=\frac{10x-44}{(x-3)(x-5)}[/tex]
