Answer:
[tex]\frac{15x^2}{7y}[/tex]
Step-by-step explanation:
The given complex fraction is:
[tex]\frac{\frac{x+4x}{y}}{\frac{7}{3x}}[/tex]
Upon solving, we get
=[tex]\frac{x+4x}{y}{\times}\frac{3x}{7}[/tex]
=[tex]\frac{3x(x+4x)}{7y}[/tex]
=[tex]\frac{3x(5x)}{7y}[/tex]
=[tex]\frac{15x^2}{7y}[/tex]
Thus, [tex]\frac{\frac{x+4x}{y}}{\frac{7}{3x}}=\frac{15x^2}{7y}[/tex]
which is the required simplified form.
