Respuesta :
X₂O₃ ===> 3 moles of oxygen == > 48 g O
Molar mass of X₂O₃-------------- 48g O
30,6g --------------------------------- 14,4g
Molar mass = (30,6×48)/14,4
Molar mass = 102g
Molar mass of X₂ = 102 - 48 = 54g
Molar mass of X = 54/2 = 27g
X ==> 27 g/mol ==> Al
X₂O₃ ==> Al₂O₃
:)
Molar mass of X₂O₃-------------- 48g O
30,6g --------------------------------- 14,4g
Molar mass = (30,6×48)/14,4
Molar mass = 102g
Molar mass of X₂ = 102 - 48 = 54g
Molar mass of X = 54/2 = 27g
X ==> 27 g/mol ==> Al
X₂O₃ ==> Al₂O₃
:)
Answer:
27 g/mol
Explanation:
To calculate the molar mass of element X, we need to calculate the mass in a given number of moles.
- The moles of X can be calculated by using the ratio of O atoms to X atoms in the molecule:
[tex]14.4 g O*\frac{1molO}{16gO} *\frac{2molX}{3molO}=0.60 mol X[/tex]
- The mass of X₂O₃ that is not oxygen, is element X. In other words, the mass of the atoms of the X element contained in the 30.6 g sample is:
30.6 g - 14.4 g = 16.2 g of X
Thus, the molar mass of element X is
16.2 g / 0.60 mol = 27 g/mol