Respuesta :

konrad509
[tex]d=\sqrt{(5-0)^2+(4-0)^2}=\sqrt{25+16}=\sqrt{41}[/tex]

Answer:

Distance between 5 and 4i is:

6.40

Step-by-step explanation:

The distance(d) between the points a+ib and c+id is calculated by

[tex]d=\sqrt{(a-c)^2+(b-d)^2}[/tex]

Here a=5,b=0 and c=0,d=4

[tex]d=\sqrt{(5-0)^2+(0-4)^2}[/tex]

[tex]d=\sqrt{25+16}[/tex]

[tex]d=\sqrt{41}[/tex]

Hence, d=6.40

Hence, distance between 5 and 4i is:

6.40

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