Answer:
x=1 and is not extraneous.
Step-by-step explanation:
We have been given the equation:
[tex]\sqrt{x+3}+4=6[/tex]
collect terms without square root so, we will shift 4 on the right hand side of the equation.
Hence, equation becomes:
[tex]\sqrt{x+3}=6-4[/tex]
[tex]\sqrt{x+3}=2[/tex]
Now, squaring both sides so, as to remove square root we get:
[tex]{x+3}=4[/tex]
[tex]x=1[/tex]
At x=1 is not extraneous because extraneous is the point where we get zero at that point in a function.
