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Which of the following is a result of shifting a circle with equation (x - 5)^2 + (y - 6)^2 = 36 to the right 2 units?
A. Both the x- and y-coordinates of the center of the circle decrease by 2.
B. The y-coordinate of the center of the circle increases by 2.
C. The x-coordinate of the center of the circle increases by 2.
D. Both the x- and y-coordinates of the center of the circle increase by 2.

Respuesta :

recall,

Circle centered at (h,k) and radius r --

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Here it is a circle centered at (h,k)=(5,6) and radius r=6
If you move to the right, the x coordinate will increase, so here the only change is the x coordinate increases by 2.
[tex](x-5)^2+(y-6)^2=r^2[/tex]
[tex](x-7)^2+(y-6)^2=6^2[/tex]
 
budwilkins
C. The x-coordinate of the center of the circle increases by 2.
Because the equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2, where the center of the circle is at (h, k), and the radius of the circle = r
So the center of this circle is at (5, 6).
To shift it to the right 2 units means to make the center 5+2=7, with no change in y or r.

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