contestada

Aluminum reacts with sulfuric acid to produce aluminum sulfate and hydrogen gas. how many grams of aluminum sulfate would be formed if 250 g hso completely reacted with aluminum?

Respuesta :

atomic weights S-32 O-16 Al-27 H-1
aluminium sulfate 250g= 2.55 mol  (250/98) 
3Al +  2H2SO4 --------->  Al2(SO4)3 + 2H2 
therefore  two parts of sulfuric acid produces one part of aluminum sulfate. 

2.55mol /2 =1.275 mol  1.275mols of aluminium sulfate is produced.  

1.275mol s multiplied by aluminium sulfate's molar mass (342g/mol) gives it's mass in grams.. 

how many grams of aluminium sulfate produced ? 436.22 g  HOPE THIS HELPS GOOD LUCK  
sebassandin

Answer:

[tex]m_{Al_2(SO_4)_3}=291gAl_2(SO_4)_3[/tex]

Explanation:

Hello,

In this case, the undergoing reaction is:

[tex]2Al(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2(g)[/tex]

In such a way, from the 250 g of sulfuric acid that completely reacts with the aliminium, the yielded grams of aluminium sulfate are computed by considering the 3 to 1 molar relationship between sulfuric acid and aluminium sulfate and the corresponding molar masses of 98 g/mol and 342 g/mol respectively:

[tex]m_{Al_2(SO_4)_3}=250gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}*\frac{1molAl_2(SO_4)_3}{3molH_2SO_4} *\frac{342gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=291gAl_2(SO_4)_3[/tex]

Best regards.

Otras preguntas