gurveer07
contestada

What is the equation in point slope form of the line that is parallel to the given line and passes through the point (4,1)

Y-1=-2(x-4)

Y-1=-1/2(x-4)

Y-1=1/2(x-4)

Y-1=2(x-4)

What is the equation in point slope form of the line that is parallel to the given line and passes through the point 41 Y12x4 Y112x4 Y112x4 Y12x4 class=

Respuesta :

tonb
The slope will be the same, so we know the equation will be y=-2x+b. But there is a different b.

For x=4, y will be 1 because the point (4,1) is given.

So 1=-2*4 + b => b = 9

So the equation of our parallel line is y=-2x+9

If we subtract 1 from both sides, we get y-1 = -2x + 8
Then factor out -2 on the right hand side: y-1 = -2(x - 4)

That's answer A!
ashishdwivedilVT

The equation in point slope form of the line that is parallel to the given line and passes through the point (4,1) is ( y - 1 ) = -1/2 (x - 4)

What is Slope Point form?

Point-slope is the general form y-y₁=m(x-x₁) for linear equations. It emphasizes the slope of the line and a point on the line (that is not the y-intercept).

Given line passing through point (-3, 3) and (-2, 1)

Slope of given equation = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

                                  m₁ = [tex]\frac{-2-(-3)}{1-3}[/tex]

                                  m₁ = 1/-2

                                  m₁ = -1/2

Slope of parallel line m₂ = m₁

                                   m₂ = -1/2

Passing point (4, 1)

Equation of line in slope point form:

(y - y₁) = m₂ (x - x₁)

( y - 1 ) = -1/2 (x - 4)

Thus, The equation in point slope form of the line that is parallel to the given line and passes through the point (4,1) is ( y - 1 ) = -1/2 (x - 4)

Learn more about Slope point form:

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