In a binomial experiment, the probability that a person scores a point is given as 29%. if he tries 69 times, what is the standard deviation of this binomial experiment? round your answer to 4 decimal places.
In binomial distribution, n=sample size =69 p=probability of success = 0.29 mean = np = 69*.29= 20.0100 variance = npq = np(1-p) =20.01(1-0.29)=14.20710 standard deviation=sqrt(variance)=3.76923 (round to appropriate number of decimal places)
