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Find the area of segment CFD given the following information:
radius = 20in, area of ΔCBD = 178.2in2, and m∠CBD = 63°
Round your answer to the nearest hundredths if necessary.

41.71 in2
95.20 in2
89.10 in2
83.42 in2

Please help me ASAP Find the area of segment CFD given the following information radius 20in area of ΔCBD 1782in2 and mCBD 63 Round your answer to the nearest h class=

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The area of segment CFD will be equal to 41.71 square inches.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

  • radius = 20in, area of ΔCBD = 178.2in2, and m∠CBD = 63°

The area of the sector CFD will be calculated as:-

The area of Sector CFDB is calculated by the formula;-

A  =  [tex]\dfrac{\pi r^2 \theta}{360}[/tex]

A  =  [tex]\dfrac{\pi \times (20^2)\times 63}{360}[/tex]

A  =  219.9 square inches

The area of the triangle is ΔCBD = 178.2in2

Now the area of sector CFD will be = Area of Sector CFDB -  Area ΔCBD

Area CFD  = 219.9  -   178.2

Area CFD  = 41.71 square inches

Therefore the area of segment CFD will be equal to 41.71 square inches.

To know more about an area follow

https://brainly.com/question/25292087

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