Respuesta :

 We are given with the rate constant of a first-order decomposition of n2o which is equal to 3.40 s-1. Half life of the radioactive material can be determined through the formula: t= ln2 /k where t is the half life of the material. t then upon substitution is equal to 0.2048 s. 

Answer : The half-life of the decomposition is, 0.203 seconds.

Solution :

Half-life period of a first order reaction is defined as the the time taken for any fraction of the reaction to complete is independent of the initial concentration.

Formula of the half-life period of a first order reaction will be,

[tex]t_{1/2}=\frac{0.693}{k}[/tex]

where,

[tex]t_{1/2}[/tex] = half-life of the reaction

k = rate constant = [tex]3.40s^{-1}[/tex]

Now put all the values in this formula, we get the half-life of the reaction.

[tex]t_{1/2}=\frac{0.693}{3.40s^{-1}}=0.203s[/tex]

Therefore, the half-life of the decomposition is, 0.203 seconds.