What is the equation in point slope form of a line that is parallel to the given line and passes through the point (4,1)

What is the equation in point slope form of a line that is parallel to the given line and passes through the point 41 class=

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The equation will have the form y=ax+b. a is the slope, and b is the y value at x=0.

The slope is -2 (that's our a), which you can see from the two given points. If x progresses from -3 to -2, y goes from 3 to 1. At x=0, the line crosses through y=-3 (that's our b)

So our generic form y=ax+b for this line is y=-2x-3

Answer:

Y - 1 = -2(x - 4)

Step-by-step explanation:

Point-slope form: y - y1 = m(x - x1)

We are given the points, (4,1) and we know the slope of the line is -2. Since we are finding a parallel line of the original line, the slope must be the same.

To write an equation in point-slope form that passes (4,1), substitute the x and y coordinates in the form and the slope.

The equation should look like this:

Y - 1 = -2(x - 4)

Where 1 and 4 are the given points and -2 is the slope.

I hope this helps!