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Suppose the population of a town is 567 in 2001. The population decreases at a rate of 1.5% every year. What will be the population of the town in 2010? Round your answer to the nearest whole number.

1.) A is congruent to 487 people
2.) A is congruent to 467 people
3.) A is congruent to 495 people
4.) A is congruent to 465 people

Respuesta :

musiclover10045

for the formula is

 Y = starting population x (1-rate of change)^number of years

2010-2001 = 9

Y= 567 x (1-0.015)^9 = 494.89, round up to 495 people

Answer:

The answer is 495 people.

Step-by-step explanation:

In 2001, the population of the town is = 567

The population decreases at a rate of 1.5% every year.

This is an exponential decrease, so we can write the expression as :

[tex]((1-.015)^9)(567)[/tex]

= [tex]((0.985)^9)(567)[/tex]

[tex]0.87282\times567[/tex] = 494.888 ≈ 495

Therefore, the answer is 495 people.

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