Respuesta :
a = vt^2/r
vt^2 = a × r
vt = √(a × r)
vt = √(42 m/s^2 × 0.23 m)
vt = √9.66 m^2/s^2
vt = 3.108 m/s
vt^2 = a × r
vt = √(a × r)
vt = √(42 m/s^2 × 0.23 m)
vt = √9.66 m^2/s^2
vt = 3.108 m/s
The tangential velocity is 3.108m/s.
To find the answer, we need to know about the relation between centripetal acceleration and tangential velocity.
What is centripetal acceleration?
- When an object moves in a circular path, it experiences only the centripetal force in inertial frame.
- This centripetal force gives the centripetal acceleration which is (tangential velocity)²/radius.
What is the tangential velocity, if centripetal acceleration is 42m/s² and radius is 0.23m?
- From the mathematical expression of centripetal acceleration, we have the tangential velocity=√(acceleration×radius)
- So, tangential velocity=√(42×0.23)= 3.108m/s
Thus, we can conclude that the tangential velocity is 3.108m/s.
Learn more about the centripetal acceleration here:
brainly.com/question/79801
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