Respuesta :

a = vt^2/r
vt^2 = a × r
vt = √(a × r)
vt = √(42 m/s^2 × 0.23 m)
vt = √9.66 m^2/s^2
vt = 3.108 m/s

The tangential velocity is 3.108m/s.

To find the answer, we need to know about the relation between centripetal acceleration and tangential velocity.

What is centripetal acceleration?

  • When an object moves in a circular path, it experiences only the centripetal force in inertial frame.
  • This centripetal force gives the centripetal acceleration which is (tangential velocity)²/radius.

What is the tangential velocity, if centripetal acceleration is 42m/s² and radius is 0.23m?

  • From the mathematical expression of centripetal acceleration, we have the tangential velocity=√(acceleration×radius)
  • So, tangential velocity=√(42×0.23)= 3.108m/s

Thus, we can conclude that the tangential velocity is 3.108m/s.

Learn more about the centripetal acceleration here:

brainly.com/question/79801

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