Let
D------> change in velocity in [tex] \frac{m}{s}} [/tex]
a------> acceleration in [tex] \frac{m}{s^{2}} [/tex]
t-------> is the time in sec
we know that
[tex] a=\frac{D}{t} \\ \\ D=a*t [/tex]
Find the change in velocity for each case
case 1) Kyra
[tex] a=5.2\ \frac{m}{s^{2}} \\ \\ t=6.9\ s [/tex]
Substitute in the formula above
[tex] D=a*t\\ D=5.2*6.9\\ D=35.88\ \frac{m}{s} [/tex]
case 2) Dustin
[tex] a=8.3\ \frac{m}{s^{2}} \\ \\ t=3\ s [/tex]
Substitute in the formula above
[tex] D=a*t\\ D=8.3*3\\ D=24.9\ \frac{m}{s} [/tex]
case 3) Diego
[tex] a=6.5\ \frac{m}{s^{2}} \\ \\ t=4.2\ s [/tex]
Substitute in the formula above
[tex] D=a*t\\ D=6.5*4.2\\ D=27.3\ \frac{m}{s} [/tex]
So
The list from greatest to lowest change in velocity is
Kira ([tex] 35.88\ \frac{m}{s} [/tex]) → Diego ([tex] 27.3\ \frac{m}{s} [/tex]) → Dustin ([tex] 24.9\ \frac{m}{s} [/tex])
therefore
the answer is the option
d. Kira → Diego → Dustin
