Answer:
[tex]25z^{4} +30z^{3} +29z^{2} +12z+4[/tex]
Step-by-step explanation:
The trinomial is squared, so it can be solved with the following notable product
[tex](a+b+c)^{2} = a^{2} +b^{2} +c^{2} +2ab+2ac+2bc[/tex]
If we substitute the indicated values
[tex]a=5z^{2} ; b=3z; c=2[/tex]
Tendremos lo siguiente
[tex](5z^{2} +3z+2)^{2} = (5z^{2} )^{2} +(3z)^{2} +2^{2} +2(5z^{2} )(3z)+2(5z^{2} )(2)+2(3z)(2)[/tex]
performing indicated operations
[tex]25z^{4} +9z^{2} +4+30z^{3} +20z^{2} +12z[/tex]
accommodating terms
[tex]25z^{4} +30z^{3} +9z^{2} +20z^{2} +12z+4[/tex]
reducing terms
[tex]25z^{4} +30z^{3} +29z^{2} +12z+4[/tex]
